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marcelo_bahia
Joined: 15 May 2009
Posts: 4
Location: argentine
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Posted: 22 June 2009, 16:54 PM Post subject: com2 ,problems with bit stop |
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I use the following configuration in Z24-P to transmit,com2 only tx pin11 8-p-2
(8 data bits, even parity, 2 stop bits at 115000.)
my problem is that no appear 2 stop bits y and alters the output bit
will have some problem with the progracion, which may be the error?
the z24 has a max232 connected, the images are a departure max232,view photo 8-p-1 (1 bit stop) and 8-p-2 (2 bit stop).
| Code: | Const txPin as Byte = 11
Const channel as Byte = 2
Dim oq(1 to 40) as Byte
Dim b as Byte
Dim i as Byte
Dim Bstop as Byte
Sub Main()
Bstop=2
b=75 'letter K in ascii
' initialize the queues
Call OpenQueue(oq)
' define the characteristics of the serial channel ,( channel 2,no Rx,only tx,8bitdata and 2bit parity even,bit stop)
Call DefineCom(2, 0,txPin, &H38,Bstop)
' open the serial channel
Call OpenCom(2, 115600, 0, oq)
do
'output port serie com2 micro
Call PutQueue(oq,b,1)
Call PutQueue(oq,b,1)
loop |
[admin edit: added code tags]
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Schematic Z24 max232.doc |
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com_2.bas |
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from Max232 tx ,Z24 set com2 tx 8bit Parity even 2 bit stop |
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set 8-p-2.jpg |
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55.06 KB |
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from Max232,Z24 set com2 tx 8bit parity even 1 bit stop |
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set 8-p-1.jpg |
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60.92 KB |
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dkinzer Site Admin
Joined: 03 Sep 2005
Posts: 2493
Location: Portland, OR
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Posted: 22 June 2009, 17:54 PM Post subject: Re: com2 ,problems with bit stop |
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| marcelo_bahia wrote: | | my problem is that no appear 2 stop bits | You have discovered a previously undetected problem that seems to have been introduced around v2.5.0 of the VM. You can work around the issue by specifying a larger value for the stopBits parameter to DefineCom(), for example: | Code: | Call DefineCom(2, 0, 0, &H38, 3)
| This works because the maximum number of stop bits on a hardware UART channel is two and, as the documentation states, any value above 1 will select two stop bits.
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marcelo_bahia
Joined: 15 May 2009
Posts: 4
Location: argentine
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Posted: 23 June 2009, 11:58 AM Post subject: |
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results
1)changing Call DefineCom(2, 0,0, &H38,3) ,for 2 stop bits as shown in photo 3 bit.jpg
2)changing Call DefineCom(2, 0,0, &H38,2) ,for 1 stop bits as shown in photo 2 bit.jpg
thank you Don
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2 bit.jpg |
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3 bit.jpg |
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59.75 KB |
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2766 Time(s) |
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